for the matrix
Show that A3– 6A2 + 5A + 11 I = O. Hence, find A–1.
Solution :-
Multiply A with A to get A2
Multiply A2 with A again to get A3
Now plug the value in equation A3– 6A2 + 5A + 11I = O we get
Hence A3– 6A2 + 5A + 11I = O
Multiply equation by A-1 to get A-1
We get
A3 A-1 – 6A2A-1 + 5A A-1 + 11I A-1 = O A-1
Solve it we get
A2– 6A + 5I + 11 A-1= O
11A-1 = – A2 + 6A – 5I
Plug the value we get
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