Method - 2
mass of sodium acetate = (malrity * molar mass * volume of soultion in ml ) /1000
= .375 * 82.0245 *500/1000 = 15.38 g
0.375 M aqueous solution of sodium acetate = 1000 mL of solution containing 0.375 moles of sodium acetate
Method - 3
Number of moles of sodium acetate in 500 mL
Molar mass of sodium acetate = 82.0245 g mole–1 (Given)
∴ Required mass of sodium acetate = (82.0245 g mol–1) (0.1875 mole)
∴ Required mass of sodium acetate = (82.0245 g mol–1) (0.1875 mole)
Method - 4
You need 500 ml of 0.375 moles/l solution
500ml * 0.375mole/1000ml = 0.1875 moles
1 mole = 82.0245 g
0.1875 moles * 82.0245 g/mole = 15.379 g
take 15.38 g and dissolve to make a 500 ml solution and it will be 0.375 M
500ml * 0.375mole/1000ml = 0.1875 moles
1 mole = 82.0245 g
0.1875 moles * 82.0245 g/mole = 15.379 g
take 15.38 g and dissolve to make a 500 ml solution and it will be 0.375 M
Method - 5
first, figure how many moles of sodium acetate / ml of water
you need to produce a 0.375molar sol, do you know your units?
a 1 molar solution = 1mole / litre...
you'll have to forgive chemists for their definitions.
0.375molar solution = 0.375mole / litre
1000mL = 1L
from this : 0.1875moles of sodium acetate multiply by molar
mass and you get your answer.
you need to produce a 0.375molar sol, do you know your units?
a 1 molar solution = 1mole / litre...
you'll have to forgive chemists for their definitions.
0.375molar solution = 0.375mole / litre
1000mL = 1L
from this : 0.1875moles of sodium acetate multiply by molar
mass and you get your answer.
Method - 6
