Q 1.16:A compound is formed by two elements M and N. The element N forms ccp and atoms of M occupy 1/3rd of tetrahedral voids. What is the formula of the compound?
Solution:
Let number of atoms of the element N = n
Number of tetrahedral voids = 2 × number of atoms in close packaging
Therefore
Number of tetrahedral voids = 2n
It is given that the atoms of element M occupy 1/3rd of tetrahedral voids.
So that the number of atoms of M is = (1/3) × 2n
=(2/3)n
Ratio of the number of atoms of M and N
Multiply by 3 and divide by n we get
M:N = 2:3
Hence , the formula of the compound is M2N3.
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