Five years ago,Nuri was thrice as old as Sonu. Ten years later,Nuri will be twice as old as Sonu. How old are Nuri and Sonu?
Let the present age of Nuri = x year
And present age of Sonu = y year
Five years ago
Age of Nuri = x – 5 years
Age of Sony = y – 5 years
Nuri was thrice as old as Sonu
X- 5 = 3(y – 5)
X – 5 = 35 – 15
X – 3y = -15 + 5
X – 3 y = - 10 ………..(1)
Ten years later,
Age of Nuri = x + 10
Age of Sonu = y + 10
Nuri will be twice as old as Sonu.
X+ 10 = 2(y+10)
X + 10 = 2y + 20
X – 2y = 10 ………..(2)
X – 3 y = - 10 ………..(1)
Subtracting equation (1) from equation (2) we get
Y = 20
Plug this value in equation first we get
X - 3* 20 = -10
X = 60 – 10
X = 50
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