The partial pressure of ethane over a solution containing 6.56 × 10–3 g of ethane is 1 bar. If the solution contains 5.00 × 10–2 g of ethane, then what shall be the partial pressure of the gas

The partial pressure of ethane over a solution containing 6.56 × 10–3 g of ethane is 1 bar. If the solution contains 5.00 × 10–2 g of ethane, then what shall be the partial pressure of the gas?

Answer

Step -1 (What is given in problem ?)

condition -1

Partial pressure of ethane = 1 bar

Mass of ethane =6.56 × 10–3 g
Condition -2
Now mass of ethane is 5.00 × 10–2
We have to find the pressure

So using Henry’s law 

Mass of dissolved gas(m) of directly proportional to its pressure (p)

m= kp   here k is proportionality constant

so plug the values we get

m1= kp1 ……………(1)

m2 = kp2 …………...(2)

Divide equation (2) by (1) equation we get

M2/m1 = p2/p1

Multiply by p1 both sides we get

P2 = m2*p1/m1

Plug the values now we get

                           P2 = 5.00 × 10–2* 1/6.56 × 10–3 g

                         P2= 7.62 bar (Answer)