A reaction is first order in A and second order in B. (i)Write the differential rate equation. (ii) How is the rate affected on increasing the concentration of B three times? (iii) How is the rate affected when the concentrations of both A and B are doubled?

Question 4.9: A reaction is first order in A and second order in B.
(i)Write the differential rate equation.
(ii) How is the rate affected on increasing the concentration of B three times?
(iii) How is the rate affected when the concentrations of both A and B are doubled?
Answer
Given that
Order of reactant A, x = 1
Order of reactant B, y = 2
The differential rate equation will be

Plug the value in this formula

Given that concentration of B is increased three times
So that
New concentration of B = 3[B]
Plug the values we get new rate of reaction

Hence, the rate of reaction will increase by 9 times.
(iii)
Given that
New concentrations of A = 2[A]
New concentration of B = 2[B]
Plug the values we get

Hence the rate of reaction increased by 8 times