The decomposition of dimethyl ether leads to the formation of CH4, H2 and CO and the reaction rate is given by
Rate = k [CH3OCH3]3/2
The rate of reaction is followed by increase in pressure in a closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether, i.e.,
Rate = k [CH3OCH3]3/2
If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constants?
Answer
Given that
Rate = k [CH3OCH3]3/2
In this problem pressure is in bar and time in minutes so that Unit of rate = bar min−1
Given that Rate = k [CH3OCH3]3/2
unit of k = unit of rate / unit of [CH3OCH3]3/2
Hence unit of K = bar min -1/ bar3/2
= bar-1/2 min-1
Rate = k [CH3OCH3]3/2
The rate of reaction is followed by increase in pressure in a closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether, i.e.,
Rate = k [CH3OCH3]3/2
If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constants?
Answer
Given that
Rate = k [CH3OCH3]3/2
In this problem pressure is in bar and time in minutes so that Unit of rate = bar min−1
Given that Rate = k [CH3OCH3]3/2
unit of k = unit of rate / unit of [CH3OCH3]3/2
Hence unit of K = bar min -1/ bar3/2
= bar-1/2 min-1
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