Q.14: How much electricity is required in coulomb for the oxidation of
(i) 1 mol of H2O to O2.
(ii) 1 mol of FeO to Fe2O3.
Solution:
(i) We have 1 mol of H2O
1 mol of H2O will give one atom of O
Charge on O = – 2
Electricity required =n F
= 2 × 96487 Coulombs
= 192974 Coulombs
= 1.93 × 105 Coulombs
(ii)
Charge on Fe in compound FeO = + 2
Charge on Fe in compound Fe2O3 = + 3
Change in charge n = 1
Electricity required = nF
= 96487 Coulombs
= 9.65 × 104 Coulombs
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