A battery of 9 V is connected in series with resistors of

Question 9:

A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω, 0.5 Ω and 12 Ω, respectively. How much current would flow through the 12 Ω resistor?

Solution:

There is no current division occurring in a series circuit. Current flow through the component is the same.

Resistances are connected in series. Hence, the sum of the resistances will give the value of R. R = 0.2 + 0.3 + 0.4 + 0.5 + 12 = 13.4 Ω

Potential difference, V = 9 V

∴ the current that would flow through the 12 Ω resistor will be 0.671 A.