Show that the relation R in R defined as R = {(a, b): a ≤ b}, is reflexive and transitive but not symmetric.

Question 4: Show that the relation R in R defined as R = {(a, b): a ≤ b}, is reflexive and transitive but not symmetric.

Answer: R = {(a, b); a ≤ b}

Clearly (a, a) ∈R as a = a.

∴R is reflexive.

Now, (1, 3) ∈R (as 1 < 3)

But, (3, 1) ∉ R as 3 is greater than 1.

∴R is not symmetric.

Now, let (a, b), (b, c) ∈ R.

Then,

a ≤ b and b ≤ c

⇒ a ≤ c

⇒(a, c) ∈ R

∴R is transitive.

Hence the relation R in R defined as R = {(a, b): a ≤ b}, is reflexive and transitive but not symmetric