Sunday, March 31, 2013

The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 2 more balls of the same kind for Rs 1300. Represent this situation algebraically and geometrically


The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 2 more balls of the same kind for Rs 1300. Represent this situation algebraically and geometrically.
Let cost of one bat  = Rs x
Cost of one ball      = Rs y
 3 bats and 6 balls for Rs 3900 So that
3 x + 6y = 3900                     … (1)
Divide complete equation by 3 we get
x+ 2y = 1300                       
Subtract 2y both side we get
x = 1300 – 2y  
 Plug y = - 1300, 0 and 1300  we get
x = 1300 – 2 ( - 1300 )   = 1300 + 2600   =  3900
x= 1300 -2(0)                = 1300 -0          = 1300
x= 1300 – 2(1300)         = 1300 – 2600   = - 1300  

X
3900
1300
-1300
y
-1300
0
1300

Given that  she buys another bat and 2 more balls of the same kind for Rs 1300
So we get
x  + 2 y = 1300                      … (2)
Subtract 2y both side we get
         = 1300 – 2y
 Plug y = - 1300, 0 and 1300  we get
x        = 1300 – 2 ( - 1300 )              = 1300  +  2600        =  3900
x         = 1300 – 2 ( 0 )                     = 1300 - 0                = 1300
x         = 1300 – 2(1300)                  = 1300 – 2600           = -1300

X
3900
1300
-1300
y
-1300
0
1300


                                   
Algebraic representation
3 x + 6 y = 3900                    … (1)
x + 2 y    = 1300                     … (2)

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