Sunday, March 31, 2013

Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is 36 m. Find the dimensions of the garden.


Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is 36 m. Find the dimensions of the garden.
Let length of rectangle        = x m
With of the rectangle           = y m
Given that whose length is 4 m more than its width
so  that
x          = 4 + y
plug  y = -18 , 0, and 18 we get
x          = 4 - 18           = -14
x          = 4 +0             =  0
x          = 4 + 18          = 22
X
-14
0
22
y
-18
0
18

Given that Half of the perimeter of the rectangle is 36 m so
Formula of perimeter of the rectangle     = 2(x+y)
Half of perimeter of rectangle                    = (1/2)*2(x + y)          =  x + y    
So our equation will
x + y  = 36
Subtract y both side we get 
X        = 36 – y
Plug  y = 36 ,18 and 0 we get
X         = 36 – 36        = 0
X         = 36 – 18        = 18
X         = 36 – 36        = 0
X
0
18
36
y
36
18
0
 
Hence length of garden = 20 m
Width of garden = 16 m

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