Sunday, March 31, 2013

Draw the graphs of the equations x – y + 1 = 0 and 3x + 2y – 12 = 0. Determine the coordinates of the vertices of the triangle formed by these lines and the x-axis, and shade the triangular region.


Draw the graphs of the equations x y + 1 = 0 and 3x + 2y – 12 = 0. Determine the
coordinates of the vertices of the triangle formed by these lines and the x-axis, and
shade the triangular region.
First equation is                   x – y + 1         = 0
Add y and subtract 1 both side we get
                    = y -1
Plug  y = 0 ,1 and 2 we get
  = 0 -1   = - 1
  = 1 -1   = 0
   = 2 -1   =  1
X
-1
0
1
Y
0
1
2



3x + 2y – 12   = 0
Subtract 3x and add 12 both side we get
2y        = 12 – 3x
Divide by 2 we get
y         = 6- 1.5 x
Plug  x = 0 ,2, and 4 we get
        = 6- 1.5 *0      = 6
y         = 6- 1.5 *2     = 3
        = 6- 1.5 *4      = 0
X
0
2
4
Y
6
3
0


  

Draw the graphs of the equations x – y + 1 = 0 and 3x + 2y – 12 = 0. Determine the  coordinates of the vertices of the triangle formed by these lines and the x-axis, and  shade the triangular region.
Both lines are intersects at x = 3 and y = 2
Hence answer is x = 3 and y = 2

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